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Addition of excess aqueous ammonia to a pink coloured aqueous solution of MCl2.6H2O (X)...

Addition of excess aqueous ammonia to a pink coloured aqueous solution of MCl2.6H2O (X)MCl2.6H2O (X) and NH4ClNH4Cl gives an octahedral complex Y in the presence of air. In aqueous solution, complex Y behaves as 1 : 3 electrolyte. The reaction of X with excess HCl at room temperature results in the formation of a blue coloured complex Z. The calculated spin only magnetic moment of X and Z is 3.87 B.M., whereas it is zero for complex Y.
Among the following options, which statement(s) is(are) correct ?
When X and Z are in equilibrium at 0°C, the colour of the solution is pink
The hybridization of the central metal ion in Y is d2sp3d2sp3
Z is atetrahedral complex
Addition of silver nitrate to Y gives only two equivalents of silver chloride
Solution:

Cobalt salts are pink in anhydrous & blue in hydrated form

(i)  Hybridisation of (Y) is d2sp3d2sp3 as NHNHis a strong field ligand

(ii)  [CoCl4]2-[CoCl4]2− have sp3sp3 hybridisation as Cl-Cl− is a weak field ligand

(iii)   

(iv)