Among NiCO4, NiCl42-, CoNH34Cl2Cl, Na3CoF6, Na2O2 and CsO2, the total number of paramagnetic compounds is 2 3...

2 months ago 1

Among

[N i {(C O)}_{4}], {[N i C l_{4}]}^{2 -}, [C o {(N H_{3})}_{4} C l_{2}] C l, N a_{3} [C o F_{6}], N a_{2} O_{2}

$[N i {(C O)}_{4}], {[N i C l_{4}]}^{2 -}, [C o {(N H_{3})}_{4} C l_{2}] C l, N a_{3} [C o F_{6}], N a_{2} O_{2}$ and

C s O_{2}

$C s O_{2}$ , the total number of paramagnetic compounds is

2

$2$

3

$3$

4

$4$

5

$5$

Solution:

	Compound/Ion		Unpaired Electron	Magnetic nature of compound
1]	$[N i {(C O)}_{4}]$ $[N i {(C O)}_{4}]$	${3d}^{10}, {sp}^{3}$ ${3d}^{10}, {sp}^{3}$	$0$ $0$	Diamagnetic
2]	$[C o {(N H_{3})}_{4} C l_{2}] C l$ $[C o {(N H_{3})}_{4} C l_{2}] C l$	$3 d^{6}, d^{2} {sp}^{3}$ $3 d^{6}, d^{2} {sp}^{3}$	$0$ $0$	Paramagnetic
3]	${[N i C l_{4}]}^{2 -}$ ${[N i C l_{4}]}^{2 -}$	$3 d^{8}, {sp}^{3}$ $3 d^{8}, {sp}^{3}$	$2$ $2$	Diamagnetic
4]	$N a_{3} [C o F_{6}]$ $N a_{3} [C o F_{6}]$	$3 d^{6}, {sp}^{3} d^{2}$ $3 d^{6}, {sp}^{3} d^{2}$	$4$ $4$	Paramagnetic
5]	$N a_{2} O_{2}$ $N a_{2} O_{2}$	$O_{2}^{2 -}$ $O_{2}^{2 -}$	$0$ $0$	Diamagnetic
6]	$C s O_{2}$ $C s O_{2}$	$O_{2}^{- 1}$ $O_{2}^{- 1}$	$1$ $1$	Paramagnetic

So, the total number of paramagnetic compounds is

3

$3$ .

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Among NiCO4, NiCl42-, CoNH34Cl2Cl, Na3CoF6, Na2O2 and CsO2, the total number of paramagnetic compounds is 2 3...

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Top Exams

Among NiCO4, NiCl42-, CoNH34Cl2Cl, Na3CoF6, Na2O2 and CsO2, the total number of paramagnetic compounds is 2 3...

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