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WBJEE\(\mathrm{NiCl}_{2}\left\{\mathrm{P}\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)\right\}_{2}\) exhibits temperature depend-ent magnetic behaviour (paramagnetic/diamagnetic). The coordination geometries of...
\(\mathrm{NiCl}_{2}\left\{\mathrm{P}\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)\right\}_{2}\) exhibits temperature depend-ent magnetic behaviour (paramagnetic/diamagnetic). The coordination geometries of \(\mathrm{Ni}^{2+}\) in the paramagnetic and diamagnetic states are respectively
Solution:
In both states (paramagnetic and diamagnetic) of the given complex, \(\mathrm{Ni}\) exists as \(\mathrm{Ni}^{2+}\) whose electronic configuration is \([\mathrm{Ar}] 3 d^{8} 4 s^{0}\).
In the above paramagnetic state the geometry of the complex is \(s p^{3}\) giving tetrahedral geometry.
The diamagnetic state is achieved by pairing of electrons in \(3 d\) orbital.
Thus, the geometry of the complex will be \(d s p^{2}\) giving square planar geometry.
In the above paramagnetic state the geometry of the complex is \(s p^{3}\) giving tetrahedral geometry.
The diamagnetic state is achieved by pairing of electrons in \(3 d\) orbital.
Thus, the geometry of the complex will be \(d s p^{2}\) giving square planar geometry.
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