Given: A charged particle is introduced at the origin $(x=0, y=0, z=0)$. initial velocity $=\vec{v}$,
uniform electric field $\vec{E}$.
uniform magnetic field $\vec{B}$.
Also the values are given the table.
we need to find the cases where the particle will move in a straight line with constant velocity.
To move a particle with constant velocity;
Fnet $=0$,
$\Rightarrow$ The electric force $=$ magnetic fore e.
$\begin{gathered} q E=q v B . \\ E=v B . \end{gathered}$
Now checking the options.
$\begin{aligned} &\text { A) (II) (iii) (s). } \\ &\text { (II) }=\vec{v}=\frac{E_0}{B_0} \hat{y} \text {. } \\ &\text { (iii) }=\vec{E}=-E_0 \hat{x} \\ &(s)=\vec{B}=B_0 \hat{Z} \text {. } \\ &-E_0 \hat{x}=E_0 \hat{B O} \hat{y}(B O \hat{z}) \\ \end{aligned}$
$\therefore$ (II) (iii) (s) is the correct option