JEE Main
JEE Advanced
NEET UG
BITSAT
COMEDK
VITEEE
WBJEEA container has a base of 50 cm×5 cm and height 50 cm, as shown in...
A container has a base of 50 cm×5 cm and height 50 cm, as shown in the figure. It has two parallel electrically conducting walls each of area 50 cm×50 cm. The remaining walls of the container are thin and non-conducting. The container is being filled with a liquid of dielectric constant 3 at a uniform rate of 250 cm3 s−1. What is the value of the capacitance of the container after 10 seconds?
[Given: Permittivity of free space ε0=9×10−12 C2 N−1 m−2, the effects of the non-conducting walls on the capacitance are negligible]
Height of the liquid column =volumebase area
⇒h=(250 cm3 s-1)×(10 s)(50 cm)×(5 cm)=10 cm
Now capacitance of the upper part can be written as,
C1=A1ε0d=[(0.50-0.10)×0.50]×(9×10-12)(5×10-2)
=0.36×10–10 F
Capacitance for the lower part can be written as,
C2=KA2ε0d=3×(0.10×0.5)×(9×10-12)5×10-2
⇒C2=0.27×10–10 F
Both part of the capacitor can be considered as connected in parallel,
Ceff=C1+C2
=63 pF
Join the conversation