A radioactive sample S1 having an activity of 5μCi has twice...
A radioactive sample S1 having an activity of 5μCi has twice the number of nuclei as another sample S2 which has an activity of 10μCi. The half lives of S1 and S2 can be
Solution:
Activity of S1=12 (activity of S2 )
or
\lambda_2 N_1=\frac{1}{2}\left(\lambda_2 N_2\right) \text { or } \frac{\lambda_1}{\lambda_2}=\frac{N_2}{2 N_1}
or
T1T2=2N1N2(T= half-life =ln2λ)N1=2N2T1T2=4
Given
∴ correct option is (a).
or
\lambda_2 N_1=\frac{1}{2}\left(\lambda_2 N_2\right) \text { or } \frac{\lambda_1}{\lambda_2}=\frac{N_2}{2 N_1}
or
T1T2=2N1N2(T= half-life =ln2λ)N1=2N2T1T2=4
Given
∴ correct option is (a).
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