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WBJEEA small object is placed 50 cm to the left of thin convex...
A small object is placed 50 cm to the left of thin convex lens of focal length 30 cm. A convex spherical mirror of radius of curvature 100 cm is placed to the right of the lens at a distance of 50 cm. The mirror is tilted such that the axis of the mirror is at an angle θ=30o to the axis of the lens, as shown in the figure. If the origin of the coordinate system is taken to be at the centre of the lens, the coordinates (in cm) of the point (x, y) at which the image is formed are:
Solution:
For lens V=(-50)(30)-50+30=75
For mirror V=(25√32)(50)25√32-50=- 50√34-√3
m=vu=h2h1⇒ h2=-(-50√34-√325√32).252
h2=+504-√3
The x coordinate of the images =50-vcos30+h2cos60 ≈25
The y coordinate of the images =vsin30 +h2sin60 ≈25√3
For lens V=(-50)(30)-50+30=75
For mirror V=(25√32)(50)25√32-50=- 50√34-√3
m=vu=h2h1⇒ h2=-(-50√34-√325√32).252
h2=+504-√3
The x coordinate of the images =50-vcos30+h2cos60 ≈25
The y coordinate of the images =vsin30 +h2sin60 ≈25√3
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