JEE Main
JEE Advanced
NEET UG
BITSAT
COMEDK
VITEEE
WBJEEA student is performing the experiment of resonance column. The diameter of the...
A student is performing the experiment of resonance column. The diameter of the column tube is \(4 \mathrm{~cm}\). The frequency of the tuning fork is \(512 \mathrm{~Hz}\). The air temperature is \(38^{\circ} \mathrm{C}\) in which the speed of sound is \(336 \mathrm{~m} / \mathrm{s}\). The zero of the meter scale coincides with the top end of the resonance column tube. When the first resonance occurs, the reading of the water level in the column is
Solution:
Considering the end correction \([e=0.3 D\) where \(\mathrm{D}=\) diameter \(]\)
\(f=n\left[\frac{v}{4(l+e)}\right]\) For first resonance, \(n=1\)
\(\therefore f=\frac{v}{4(l+0.3 D)} \Rightarrow l=\frac{v}{4 f}-0.3 D\)
or, \(l=\left(\frac{336 \times 100}{4 \times 512}\right)-0.3 \times 4=15.2 \mathrm{~cm}\)
\(f=n\left[\frac{v}{4(l+e)}\right]\) For first resonance, \(n=1\)
\(\therefore f=\frac{v}{4(l+0.3 D)} \Rightarrow l=\frac{v}{4 f}-0.3 D\)
or, \(l=\left(\frac{336 \times 100}{4 \times 512}\right)-0.3 \times 4=15.2 \mathrm{~cm}\)
Join the conversation