A thin uniform rod, pivoted at O, is rotating in the horizontal plane...
A thin uniform rod, pivoted at O, is rotating in the horizontal plane with constant angular speed ω, as shown in the figure. At time t=0, a small insect starts from O and moves with constant speed v, with respect to the rod towards the other end. It reaches the end of the rod at t=T and stops. The angular speed of the system remains ω throughout. The magnitude of the torque (|→τ|) about O, as a function of time is best represented by which plot?


Solution:
Angular momentum, |L| or L=Iω (about axis of rod) Moment of inertia of the rod-insect system. I=Irod +mx2=Irod +mv2t2 Here, m= mass of insect ∴L=(Irod+mv2t2)ω

Now |τ|=dLdt=(2mv2tω) or |τ|∝t
i.e. the graph is straight line passing through origin.
After time T,L= constant
∴|τ| or dLdt=0
i.e., when the insect stops moving, L does not change and therefore T becomes constant.

Now |τ|=dLdt=(2mv2tω) or |τ|∝t
i.e. the graph is straight line passing through origin.
After time T,L= constant
∴|τ| or dLdt=0
i.e., when the insect stops moving, L does not change and therefore T becomes constant.
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