Loading [MathJax]/jax/output/CommonHTML/jax.js
All
BE/B.Tech
MBA/PGDM
MBBS
ME/M.Tech
B.Sc
BA
B.Com
BCA
BBA/BMS
B.Sc (Nursing)

Ranking

College ranked based on real data

Indiatoday - 1740
Collegedunia - 1406
IIRF - 1684
Outlook - 1318
NIRF - 1301
Top Ranked Colleges in India ›

Find Colleges

Discover 19000+ colleges via preferences

Best MBA colleges in India
Best BTech colleges in India
Discover Top Colleges in India ›

Compare Colleges

Compare on the basis of rank, fees, etc.

IIT Madras vs IIT Delhi
IIT Madras vs IIT Bombay
Compare Colleges ›

Exams

Know more about your exams

B.Com
B.Sc
B.Sc (Nursing)
BA
BBA/BMS
BCA
BE/B.Tech
Check All Entrance Exams in India ›

College Predictor

Know your college admission chances

JEE Main
JEE Advanced
CAT
NEET
GATE
NMAT
MAT
XAT
Find Where you may get Admission ›

Course Finder

Discover top courses in Indian Colleges 2025

BE/B.Tech - 963
MBA/PGDM - 1159
ME/M.Tech - 1221
B.Sc - 1052
Get Top Courses in Indian Colleges ›

Your Gateway to Top Colleges & Exams

Discover thousands of questions, past papers, college details and all exam insights – in one place.

Popular Colleges

Top Exams

JEE MainJEE Main
JEE AdvJEE Advanced
NEET UGNEET UG
BITSATBITSAT
COMEDKCOMEDK
VITEEEVITEEE
WBJEEWBJEE

An ideal gas in a thermally insulated vessel at internal pressure = P1...

An ideal gas in a thermally insulated vessel at internal pressure = P1 , volume = V1 and absolute temperature = T1 expands irreversibly against zero external pressure, as shown in the diagram. The final internal pressure, volume and absolute temperature of the gas are P2 , V2 and T2 , respectively. For this expansion,

q=0
T2=T1
P2V2=P1V1
P2Vγ2=P1Vγ1
Solution:
Since container is thermally insulated. So, q = 0, and it is a case of free expansion therefore W = 0 and
∆E=0
So, T1=T2
Also, P1V1=P2V2