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WBJEEIn the circuit shown in the figure, there are two parallel plate capacitors...
In the circuit shown in the figure, there are two parallel plate capacitors each of capacitance C. The switch S1 is pressed first to fully charge the capacitor C1 and the released. The switch S2 is then pressed to charge the capacitor C2. After some time, S2 is released and then is S3 pressed. After some time,
Solution:
When S1 is closed,
charge on C1=2V0C
After S2 is closed, half of the change will move to C2
∴ charge on C1=122V0C
when S2 is closed,
charge on C2=V0C but with reversed polarity,
∴ Charge on upper plate =-V0C
charge on C1=2V0C
After S2 is closed, half of the change will move to C2
∴ charge on C1=122V0C
when S2 is closed,
charge on C2=V0C but with reversed polarity,
∴ Charge on upper plate =-V0C
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