In a radioactive decay chain, 90232Th nucleus decays to 82212Pb nucleus. Let Nα and Nβ...

2 months ago 1

In a radioactive decay chain,

$_{90}^{232} Th$ nucleus decays to

$_{82}^{212} Pb$ nucleus. Let

$N_{α} and N_{β}$ be the number of

$α and β^{-}$ particles, respectively, emitted in this decay process. Which of the following statements is (are) true?

$N_{α} = 5$

$N_{α} = 6$

$N_{β} = 2$

$N_{β} = 4$

Solution:

$_{90}^{232} Th$ is converting into $_{82}^{212} Pb$
Change in mass number $(A) = 232 - 212 = 20$

Mass number of an $α$ particle $= 4$
$∴$ No of $α particle = \frac{20}{4} = 5$
Due to $5 α$ particle, $Z$ will change by $10$ unit.
Since given change is $8$ , therefore no. of $β^{-}$ particle is $2$ .

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In a radioactive decay chain, 90232Th nucleus decays to 82212Pb nucleus. Let Nα and Nβ...

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In a radioactive decay chain, 90232Th nucleus decays to 82212Pb nucleus. Let Nα and Nβ...

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