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WBJEEIn thermodynamics, the P-V work done is given by w=-∫dVPext. For a system undergoing a particular process,...
In thermodynamics, the work done is given by . For a system undergoing a particular process, the work done is,
. This equation is applicable to a
Solution:
\(W=-\int P_{\text {ext }} d v\)
From van der waal equation of state for one mole gas \(p+\frac{a}{v^{2}}(v-b)=\mathrm{RT}\)
\(p=\frac{\mathrm{RT}}{(v-b)}-\frac{a}{v^{2}}\)
For reversible process
\(p_{\text {ext }}=p_{\text {gas }}\)
\(W=-\int \frac{\text {RT }}{(v-b)}-\frac{a}{v^{2}}\)
process is only not applicable for irreversible process.
From van der waal equation of state for one mole gas \(p+\frac{a}{v^{2}}(v-b)=\mathrm{RT}\)
\(p=\frac{\mathrm{RT}}{(v-b)}-\frac{a}{v^{2}}\)
For reversible process
\(p_{\text {ext }}=p_{\text {gas }}\)
\(W=-\int \frac{\text {RT }}{(v-b)}-\frac{a}{v^{2}}\)
process is only not applicable for irreversible process.
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