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The mass of a nucleus ${ }_{Z}^{A} X$ is less than the sum of the masses of $(A-Z)$ number of neutrons and $Z$ number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass $M$ can break into two light nuclei of masses $m_{1}$ and $m_{2}$ only if $\left(m_{1}+m_{2}\right) \lt M$. Also two light nuclei of masses $m_{3}$ and $m_{4}$ can undergo complete fusion and form a heavy nucleus of mass $M^{\prime}$ only if $\left(m_{3}+m_{4}\right) \gt M^{\prime}$. The masses of some neutral atoms are given in the table below:




$\left(1 u=932 M e V / c^{2}\right)$


Question:

The kinetic energy (in $k e V$ ) of the alpha particle, when the nucleus ${ }_{84}^{210} P o$ at rest undergoes alpha decay, is