Paragraph: The mass of a nucleus AZX is less than the...
Paragraph:
The mass of a nucleus AZX is less than the sum of the masses of (A−Z) number of neutrons and Z number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m1 and m2 only if (m1+m2)<M. Also two light nuclei of masses m3 and m4 can undergo complete fusion and form a heavy nucleus of mass M′ only if (m3+m4)>M′. The masses of some neutral atoms are given in the table below:

(1u=932MeV/c2)
Question:
The kinetic energy (in keV ) of the alpha particle, when the nucleus 21084Po at rest undergoes alpha decay, is
The mass of a nucleus AZX is less than the sum of the masses of (A−Z) number of neutrons and Z number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m1 and m2 only if (m1+m2)<M. Also two light nuclei of masses m3 and m4 can undergo complete fusion and form a heavy nucleus of mass M′ only if (m3+m4)>M′. The masses of some neutral atoms are given in the table below:

(1u=932MeV/c2)
Question:
The kinetic energy (in keV ) of the alpha particle, when the nucleus 21084Po at rest undergoes alpha decay, is
Solution:
84Po210+2He4→82Pb206
Δm=[MPO-MHe-MPb]=0.008421 u
Q=0.008421×932 MeV=5422 KeV
Kα=210214×5422 KeV=5320 KeV
Δm=[MPO-MHe-MPb]=0.008421 u
Q=0.008421×932 MeV=5422 KeV
Kα=210214×5422 KeV=5320 KeV
Join the conversation