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Paragraph:Scientists are working hard to develop nuclear fusion reactor. Nuclei of heavy hydrogen,...

Paragraph:
Scientists are working hard to develop nuclear fusion reactor. Nuclei of heavy hydrogen, 21H21H known as deuteron and denoted by DD can be thought of as a candidate for fusion reactor. The DD - DD reaction is 21H+21H→32He+n+21H+21H→32He+n+ energy. In the core of fusion reactor. A gas of heavy hydrogen is fully ionized into deuteron nuclei and electrons. This collection of 41H41H nuclei and electrons is known as plasma. The nuclei move randomly in the reactor core and occasionally come close enough for nuclear fusion to take place. Usually, the temperatures in the reactor core are too high and no material wall can be used to confine the plasma. Special techniques are used which confine the plasma for a time t0t0 before the particles fly away from the core. If n is the density (number/volume) of deutrons, the product t 00 is called Lawson number. In one of the criteria, aa reactor is termed successful if Lawson number is greater than 5×1014scm−35×1014scm−3.
It may be helpful to use the following : Boltzmann constant k=8.6×10−5eV/Kk=8.6×10−5eV/K; e24πε0=1.44×10−9eVme24πε0=1.44×10−9eVmQuestion:
Assume that two deuteron nuclei in the core of fusion reactor at temperature TT are moving towards each other, each with kinetic energy 1.5kT1.5kT, when the separation between them is large enough to neglect Coulomb potential energy. Also neglect any interaction from other particles in the core. The minimum temperature TT required for them to reach a separation of 4×10−15 m4×10−15 m is in the range

1.0×109 K<T<2.0×109 K1.0×109 K<T<2.0×109 K

20×109 K<T<3.0×109 K20×109 K<T<3.0×109 K

3.0×109 K<T<4.0×109 K3.0×109 K<T<4.0×109 K

4.0×109 K<T<5.0×109 K4.0×109 K<T<5.0×109 K
Solution:
From conservation of mechanical energy, we have

Ui+Ki=Uf+Uf0+2(1.5kT)=14πε0⋅(e)(e)d+0

Substituting the values, we get

T=1.4 \times 10^9 \mathrm{~K}