${\text{F}}^{-}$ and ${\text{H}}_2\text{O}$ are weak field ligands so pairing of electrons in metal cations 3d subshell will not take place.

now we have to cosider hybridization that is given in following diagram.

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$$\begin{gathered} {\text{μ}}_{\text{P}}=\sqrt{n\left(n+2\right)} \\ n=5 \\ =\sqrt{5\times 7}=\sqrt{35}\text{BM} \end{gathered}$$

$$\begin{gathered} {\text{μ}}_{\text{Q}}=\sqrt{n(n+2)} \\ n=3 \\ =\sqrt{3\times 5}=\sqrt{15}\text{BM} \end{gathered}$$

$$\begin{gathered} {\text{μ}}_{\text{R}}=\sqrt{n(n+2)} \\ n=4 \\ =\sqrt{4\times 6}=\sqrt{24}\text{BM} \end{gathered}$$
${\text{μ}}_{\text{Q}}<{\text{μ}}_{\text{R}}<{\text{μ}}_{\text{P}}$
$\text{Q < R < P}$