An ideal gas undergoes a reversible isothermal expansion from state I to state...
(pp: pressure, VV: volume, TT: temperature, HH: enthalpy, SS: entropy)
T=T= constant
ΔH=ΔU=0ΔH=ΔU=0
H=H= constant.
ΔS≠0ΔS≠0 Entropy will increase PV=PV= constant.
and during adiabatic reversible expansion.
q=0q=0
ΔU=w=−veΔU=w=−ve
so TT will decrease
ΔH=ncpΔT=-veΔH=ncpΔT=−ve
HH will decrease
ΔS=0ΔS=0 (isoentropic process)
S=S=constant. and pvr=pvr= constant.
Keeping in mind correct graph are 1,2 and 4.
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