Processing math: 100%
All
BE/B.Tech
MBA/PGDM
MBBS
ME/M.Tech
B.Sc
BA
B.Com
BCA
BBA/BMS
B.Sc (Nursing)

Ranking

College ranked based on real data

Indiatoday - 1740
Collegedunia - 1406
IIRF - 1684
Outlook - 1318
NIRF - 1301
Top Ranked Colleges in India ›

Find Colleges

Discover 19000+ colleges via preferences

Best MBA colleges in India
Best BTech colleges in India
Discover Top Colleges in India ›

Compare Colleges

Compare on the basis of rank, fees, etc.

IIT Madras vs IIT Delhi
IIT Madras vs IIT Bombay
Compare Colleges ›

Exams

Know more about your exams

B.Com
B.Sc
B.Sc (Nursing)
BA
BBA/BMS
BCA
BE/B.Tech
Check All Entrance Exams in India ›

College Predictor

Know your college admission chances

JEE Main
JEE Advanced
CAT
NEET
GATE
NMAT
MAT
XAT
Find Where you may get Admission ›

Course Finder

Discover top courses in Indian Colleges 2025

BE/B.Tech - 963
MBA/PGDM - 1159
ME/M.Tech - 1221
B.Sc - 1052
Get Top Courses in Indian Colleges ›

Your Gateway to Top Colleges & Exams

Discover thousands of questions, past papers, college details and all exam insights – in one place.

Popular Colleges

Top Exams

JEE MainJEE Main
JEE AdvJEE Advanced
NEET UGNEET UG
BITSATBITSAT
COMEDKCOMEDK
VITEEEVITEEE
WBJEEWBJEE

Shown in the figure is a semicircular metallic strip that has thickness t...

Shown in the figure is a semicircular metallic strip that has thickness t and resistivity ρ. Its inner radius is R1 and outer radius is R2. If a voltage V0 is applied between its two ends, a current I flows in it. In addition, it is observed that a transverse voltage ΔV develops between its inner and outer surfaces due to purely kinetic effects of moving electrons (ignore any role of the magnetic field due to the current). Then (figure is schematic and not drawn to scale)

I=V0tπρln(R2R1)
the outer surface is at a higher voltage than the inner surface
the outer surface is at a lower voltage than the inner surface
ΔVI2
Solution:

Resistance of the strip =ρπrtdr

R=net resistance

1R=tdrρπrtπρR2R1drr

R=πρtln(R2R1)

Hence, current i =V0R=V0tπρln(R2R1)

for elementary dr,

di=V0ρ(πrtdr)=V0tdrρπr

i=nAev

V0tdrρπr=nt(dr)ev

eE=mv2r=mV20n22ρ2π2r2×1r

mv2r=mV20n22ρ2π2r2×1r

E1r3

E=k1r3

ΔV=Edr=kR2R1drr2V20

    i2