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WBJEEFor an ideal gas, consider only P-V work in going from an initial...
For an ideal gas, consider only P-V work in going from an initial state \(\mathrm{X}\) to the final state \(\mathrm{Z}\). The final state \(\mathrm{Z}\) can be reached by either of the two paths shown in the figure. Which of the following choice(s) is (are) correct?
[Take \(\Delta \mathrm{S}\) as change in entropy and w as work done].
[Take \(\Delta \mathrm{S}\) as change in entropy and w as work done].
Solution:
\(\Delta S_{X \rightarrow Z}=\Delta S_{X \rightarrow Y}+\Delta S_{Y \rightarrow Z}\) [Entropy is a state function, hence additive]
\(w_{X \rightarrow Y \rightarrow Z}=w_{X \rightarrow Y}\) [Work done in \(Y \rightarrow Z\) is zero because it is an isochoric process].
\(w_{X \rightarrow Y \rightarrow Z}=w_{X \rightarrow Y}\) [Work done in \(Y \rightarrow Z\) is zero because it is an isochoric process].
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